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11=3x^2-6x+2
We move all terms to the left:
11-(3x^2-6x+2)=0
We get rid of parentheses
-3x^2+6x-2+11=0
We add all the numbers together, and all the variables
-3x^2+6x+9=0
a = -3; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·(-3)·9
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-12}{2*-3}=\frac{-18}{-6} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+12}{2*-3}=\frac{6}{-6} =-1 $
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